Correct Answer - A
` x_A= pt + qt^2 , x_b =rt^2 - st^3`
Velocity, ` v_A= (dx)_A)/(dt) = p+ 2 qt`
` v_B = (dx_B)/(dt) = 2 rt - 3 st^2`
Acceleration, ` a_A = (dv_A)/(dt) = 2 q , a_B= 2 r- 6 st`
The car that initially moves ahead is the one which bas largr velocity at ` t= 0. at ` t=0 , v= p` and ` v_B =0`.
So, initially car (A) moves ahead.