Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Physics by (82.2k points)
closed by
Two cars (A) and (B) travel in straight line . The distance of (A) from the starting point is given as a function of time be ` a_A (t) = pt + qt^2 `, with ` p = 2 . 60 ms^(-1)` and ` q= 1.20 ms^(-2)`. The distance of (B) from the starting pint is ` x_B (t) = rt^2 - st^3 ` are ` r= 2. 80 ms^(-2)` and ` s = 0.20 ms^(-3)`. Answer the following questions ,
Which car is ahead just after they have the starting point ?
A. ` Car (A) moves ahead `
B. Car (B) moves ahead
C. Cars (A) and (B) move simultaneously
D. Data is insufficient to decide.

1 Answer

0 votes
by (84.4k points)
selected by
 
Best answer
Correct Answer - A
` x_A= pt + qt^2 , x_b =rt^2 - st^3`
Velocity, ` v_A= (dx)_A)/(dt) = p+ 2 qt`
` v_B = (dx_B)/(dt) = 2 rt - 3 st^2`
Acceleration, ` a_A = (dv_A)/(dt) = 2 q , a_B= 2 r- 6 st`
The car that initially moves ahead is the one which bas largr velocity at ` t= 0. at ` t=0 , v= p` and ` v_B =0`.
So, initially car (A) moves ahead.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...