Question

A rubber cube of side `5 cm` has one side fixed while a tangential force equal to `1800 N` is applied to opposite face. Find the shearing strain and the lateral displacement of the strained face. Modulus of rigidity for rubber is `2.4 xx 10^(6) N//m^(2)`.

Answer 1

`l=5xx10^(-2)mimpliesF/A=etax/L`
Strain `theta`

`theta=F/(Aeta)=1800/(25xx10^(-4)xx2.4xx10^(6))`
`=180/(25xx25)=3/10`
`=0.3` radian
`x/L=0.3`
`impliesx=0.3xx5xx10^(-2)m=1.5xx10^(-2)m=1.5m`