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A stone projected at angle `theta` with horizontal from the roof of a tall building falls on the ground after three seconds. Two second after the projection it was again at the level of projection. Then the height of the building
A. `5m`
B. 25 m
C. 20m
D. 15m

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Best answer
Correct Answer - D
`2=(2u_(y))/hrArr u_(y) =10 m//s `
Now `H=-u_(y) t+1/2 g t^(2)`
`=-30 +45 =15 m`
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