Question

In the diagram shown, the displacement of particles is given as a function of time. The particle a is moving under constant velocity of `9 m//s`. The particle B is moving under variable acceleration. From time `t=0 s` to `t=6 s`. The average velocity of the particle B will be equal to :-

A. `2.5 m//s`
B. `4 m//s`
C. `9 m//s`
D. None

Answer 1

Correct Answer - C
As given `9=y//6rArr y=54 m`
Average velocity of particle
`B=("Displacement")/("time")=54/6=9 m//s`