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A particle moves with constant speed `v` along a regular hexagon `ABCDEF` in the same order. Then the magnitude of the avergae velocity for its motion form `A` to
A. F is `v/5`
B. D is `v/3`
C. C is `(vsqrt(3))/2`
D. B is v

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Best answer
Correct Answer - A::C::D
Av. Velocity `=("Displacement")/("time")`
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