Question

Seven grams of nitrogen is mixed with 12 g of oxygen in a tube and then sealed. Calculate the velocity of sound through the tube at `27^@C`.

Answer 1

`c=sqrt((gammaRT)/(M))`
Since nitrogen and oxygen are both diatomic, `gamma=1.4`
`(m_1+m_2)/(M)=(m_1)/(M_1)+(m_2)/(M_2)`
`implies(7+12)/(M)=(7)/(28)+(12)/(32)`
`impliesM=30.4`
`c=sqrt((1.4xx8.3xx300)/(30.4xx10^-3))=338.6(m)/(s)`