Correct Answer - A
a. By the graph, `W_(AB) = 0` and `W_(BC) = 8 xx 10^(4) [5 - 2] xx 10^(-3) = 240 J`
`:. W_(AC) = W_(AB) + W_(BC) = 0 + 240 = 240 J`
Now, `Delta Q_(AC) = Delta Q_(AB) + Delta Q_(BC) = 600 + 200 = 800 J`
From the first of thermodynamics,
`Delta Q_(AC) = Delta U_(AC) + Delta W_(AC)`
`implies 800 = Delta U_(AC) + 240 implies Delta U_(AC) = 560 J`