Question

If a ball of `80` kg mass hits an ice cube and temperature of ball is `100 .^(@)C`, then how much ice converted into water ? (Specific heat of ball is `0.2 cal g^(-1)`, Latent heat of ice `= 80 cal g^(-1)`)
A. 20 g
B. `200 g`
C. `2 xx 10^(3) kg`
D. `2 xx 10^(4)g`

Answer 1

Correct Answer - D
If m is the mass of ice metled, then heat spent in melting = heat supplied by the ball
`mL = sMDeltaT`
`m xx80 = 0.2 xx (80 xx 1000) xx 100`
or `m = 2 xx 10^(4) g`