Correct Answer - A::C
Process `AB` in the given figure is an isobaric process.
During this process,
`V prop T`
But ` PV=nRT`
or `PV prop T`
Therefore during this process, pressure `P` remains constant. Process `BC` is an isochoric cooling. During this process, volume of the gas remains constant but the temperature decreases.
Process `CA` is an isothermal process. During this process. volume decrease and temperature remains constant. Hence, pressure increases during this porcess. Hence, on `P-V` diagram, process `AB` will be straight line parallel to the `V-` axis, process `BC` will be straight line parallel to the `P-` axis and `CA` wil be a rectangular hyperbola. Hence, option `(c)` is correct, while `(d)` is wrong.
On `T-V` diagram, process `AB` will be a stright line parallel to the `T-` axis, during which temperature increases. Process `BC` will be a straight line passing through origin, during which temperature and pressure both decrease and process `CA` will be a straight line parallel to the `P-` axis during which pressure increase. Hence, option `(a)` is correct while `(b)` is wrong.
