Question

The time taken by a particle performing `SHM` on a straight line to pass from point `A` to `B` where its velocities are same is `2` seconds .After another `2` seconds it return to `B` The time period of oscillation is (in seconds)
A. `2`
B. `4`
C. `6`
D. `8`

Answer 1

Correct Answer - D
From the given information it can be internal that point `A` and `B` are equiliostant then main position
Hence from diagram it is colean that time period of oscillation is `= 2+ 2 xx 2 + 2 + 8 "second"`