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A vessel of volume `3V` contains a gas at pressure `4 P_(0)` and another vessel of volume `2V` contains same gas at pressure `1.5 P_(0)`. Both vessels have same temperature. When both vessels are connected by a tube of negligible volume, the equilibrium is `IP_(0)`, where `I` is an integer. Find the value of `I`.

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Correct Answer - 3
No change of temperature
So, `(n_(1) + n_(2))_(i) = (n_(1) + n_(2))_(f)`
`(P_(1) V_(1))/(RT) + (P_(2) V_(2))/(RT) = (PV_(1))/(RT) + (PV_(2))/(RT)`
So. `P = (P_(1) V_(1) + P_(2) V_(2))/(V_(1) + V_(2))`
`= ((4 P_(0)) (3V) + (1.4 P_(0)) (2V))/(5V) = 3 P_(0) = IP_(0)` (Given)
So, `I = 3`

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