A particle of `m` is executing `SHM`about the origin on x- axis frequencxy `sqrt((ka)/(pi m))`, where `k` is a constant and a is the amplitude Find its potential energy if `x` is the displecement at time t:
A. `kax^(2)`
B. `ka^(2)x`
C. `2pi kax^(2)`
D. `2pi kx^(2)`