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P-V plots for two gases during adiabatic processes are shown in the figure. Plots 1 and 2 should corresponds respectively to
image
A. `He` and `O_2`
B. `O_2` and `He`
C. `He` and `Ar`
D. `O_2` and `N_2`

1 Answer

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Best answer
Correct Answer - B
For adiabatic process, `PV^(gamma)=`constant
For monatomic gas, `gamma=(C_(p))/(C_(v))=1.67`
For diatomic gas, `gamma=1.4`
Since `gamma_("diatomic") lt gamma_("monatomic")` , so with increase in volumem, decrease in pressure will be more for monatomic gas.
`implies` Graph `1` is for diatomic and Graph `2` is for monatomidc.
Correct option is (b) .
image

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