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One mole of an ideal gas in initial state A undergoes a cyclic process ABCA, as shown in the figure. Its pressure at A is `P_0`. Choose the correct option (s) from the following
image
A. Internal energies at A and B are the same
B. Work done by the gas in process AB is `P_0V_01n4`
C. Pressure at C is `P_0//4`
D. Temperature at C is `T_0//4`

1 Answer

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Best answer
Correct Answer - A::B
Process `AB` is isothermal. Temperature at `A` and `B` is same, so internal energy at `A` and `B` is same.
`DeltaW_(AB)=nRT_(0)ln(V_(B)//V_(A))`
For point `A:P_(0)V_(0)=nRT_(0)`
So `DeltaW_(AB)=P_(0)V_(0)ln(4V_(0)//V_(0))=P_(0)V_(0)ln(4)`
Nothing can be said about pressure and temperature at `C` .

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