Correct Answer - `(1)/(2 pi) sqrt ((k(R + r)^(2))/(I_(0) mr^(2)))`
Taking torque of spring force force about P for a small displacement of O, we have
`Kx (R + r) = I_(p) alpha , where x = (R + r) theta`
or `k(R - r) 2 theta = (mr^(2) + I_(0)) omega^(2) theta`
`omega = sqrt((k(R + r)^(2))/(mr^(2) + I_(0)))`
`f = (omega)/(2 pi) = (1)/(2 pi) sqrt ((k(R + r)^(2))/(I_(0) mr^(2)))`