Correct Answer - B
The slope of the length is
`(F)/(x)=-(0.5)/(5)=-0.1(N)/(cm)=-10(N)/(m)`
But `F=-momega^2x` or `(F)/(x)=-momega^2`
so, `-momega^2=-10` or `momega^2=10`
or `omega^2=(10)/(m)`
`omega^2=(10)/(4xx10^-1)impliesomega=(10)/(2)=5`
`f=(omega)/(2pi)=((5)/(2pi))/(s)`