Question

The potential energy of a particle executing SHM along the x-axis is given by `U=U_0-U_0cosax`. What is the period of oscillation?
A. `2pisqrt((ma)/(U_0))`
B. `2pisqrt((U_0)/(ma))`
C. `(2pi)/(a)sqrt((m)/(U_0))`
D. `2pisqrt((m)/(aU_0))`

Answer 1

Correct Answer - C
`U=U_0-U_0cosax`
`F=-(dU)/(dx)=-Usinax=m(d^2x)/(dt^2)`
This is equation of SHM `impliesT=(2pi)/(a)sqrt((m)/(U_0))`