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The displacement time graph for two sound waves A and B are shown in the figure. Then the ratio of their intensities `I_(A)//I_(B)` is equal to
A. `1:4`
B. `1:16`
C. `1:2`
D. `1:1`

1 Answer

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Correct Answer - D
Intensity `=a^2omega^2`
Here `(a_A)/(a_B)=(2)/(1)` and `(omega_A)/(omega_B)=(1)/(2)implies(l_A)/(l_B)=((2)/(1))^2xx((1)/(2))^2=(1)/(1)`

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