Correct Answer - C
The frequency of `A,n_A=n+(2)/(100)n`
And the frequency of `B,n_B=n-(3)/(100)n`
According to question `n_A-n_B=6`
`:. (n+(2)/(100)n)-(n-(3)/(100)n)=6`
or `(5)/(100)n=6impliesn=(600)/(5)=120Hz`
The frequency of A
`n_A=(n+(2)/(100)n)=120+(2)/(100)xx120=122.4Hz`