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Small amplitude progressive wave in a stretched string has a speed of `100 cm//s`.and frequency 100 Hz. The phase difference between two points 2.75 cm apart on the string in radians, is

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Correct Answer - b
`v=1 m//s, v=100 Hz`
`lambda=(v)/(v)=(1)/(100)m=1 cm`
`Deltaphi=(2pi)/(lambda)xx2.75 rad=5.5 pi rad=(11pi)/(2) rad`

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