Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.4k views
in Physics by (79.4k points)
closed by
A transverse wave travelling on a taut string is represented by:
`Y=0.01 sin 2 pi(10t-x)`
Y and x are in meters and t in seconds. Then,
A. The speed of the wave is `10m//s`.
B. closet points on the string which differ in phase by `60^(@)` are `(1//6)m` apart
C. maximum particle velocity is `pi//4 m//s`
D. the phase of a certain point on the string changes by `120^(@)` in `(1//20)` seconds.

1 Answer

0 votes
by (86.6k points)
selected by
 
Best answer
Correct Answer - a., b.
`y=0.01 sin [2pi(10t-x)]`
`impliesy=0.01sin[20pit-2pix]`
`omega=20pi, K=2pi`
Wave velocity :`v=(omega)/(k)=(20pi)/(2pi)=10m//s`
`Deltaphi=K Deltax`, given `Deltaphi=60^(@)=(pi)/(3)`
`(pi)/(3)=2pi DeltaximpliesDeltax=(1)/(6)m`
`v_(p-max)=omegaA=20pixx0.01=(pi)/(5)m//s`
`Deltaphi_(t)omegaDeltat=20pixx(1)/(20)=pi`
so in time `(1)/(20)s`, phase changes by and not `120^(@)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...