Correct Answer - a., b.
`y=0.01 sin [2pi(10t-x)]`
`impliesy=0.01sin[20pit-2pix]`
`omega=20pi, K=2pi`
Wave velocity :`v=(omega)/(k)=(20pi)/(2pi)=10m//s`
`Deltaphi=K Deltax`, given `Deltaphi=60^(@)=(pi)/(3)`
`(pi)/(3)=2pi DeltaximpliesDeltax=(1)/(6)m`
`v_(p-max)=omegaA=20pixx0.01=(pi)/(5)m//s`
`Deltaphi_(t)omegaDeltat=20pixx(1)/(20)=pi`
so in time `(1)/(20)s`, phase changes by and not `120^(@)`