Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
104 views
in Physics by (91.2k points)
closed by
A horizontal platform is rotating with uniform angular velcity around the vertical axis passing through its centre. At some instant of time a viscous fluid of mass `m` is dropped at the centre and is allowed to spread out and finally fall. The angular velocity during this period :
A. decrease continuously
B. decreases initially and increases again
C. remains unaltered
D. increases continuously

1 Answer

0 votes
by (91.8k points)
selected by
 
Best answer
Correct Answer - B
From law of conservation of angular momentum if no external torque is acting upon a body rotating about an axis, then the angular momentum of the body remains constant that is
`J = I omega =` constant
Hence, if `I` decreases , `omega` increases and vice-versa. Hence liquid is dropped, mass increases hence `I` increases `(I = mr^2)`. So, `omega` decreases, but as soon as the liquid starts falling `omega` increases again.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...