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A pulse is started at a time `t=0` along the `+x`direction on a long, taut string. The shape of the pulse at `t=0` is given by function `f(x)` with
here `f` and `x` are in centimeters. The linear mass density of the string is `50 g//m` and it is under a tension of `5N`.
There shape of the string is drawn at `t=0` and the area of the pulse enclosed by the string the x-axis is measured. it will be equjal to
A. `2 cm^(2)`
B. `2.5 cm^(2)`
C. `4 cm^(2)`
D. `5 cm^(2)`

1 Answer

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Best answer
Correct Answer - b
Shape of the pulse at `t=0`
that is a triangular pulsr.
Area of the pulse `=(1)/(2)[(4xx1)+(1xx1)]=(5)/(2)cm^(2)`
image

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