Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Physics by (79.4k points)
closed by
A plane progressive wave is given by `x=(40 cm) cos(50pit-0.02piy)` where `y` is in cm and `t` in `s`. The particle velocity at `y=25m` in time `t=(1)/(100)s` will be `10pisqrt(n) m//s`. What is the value of `n`.

1 Answer

0 votes
by (86.6k points)
selected by
 
Best answer
Given that
`x=40 cos (50pit-0.02piy)`
:. Particle velocity
`v_(p)=(dx)/(dt)=(40xx50pi){-sin(50pit-0.02piy)]`
putting `x=25` and `t=(1)/(200)s`.
`v_(p)=-(2000pi cm//s)sin[50pi((1)/(200))-0.02pi(25)]`
`=10pisqrt(2) m//s`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...