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A set of `56 `tuning forks is arranged in a sequence of increasing frequencies . If each fork gives `4 beats//s` with the preceding one and the last fork is found to be an octave higher of the first , find the frequency of the first fork.

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Correct Answer - `220 Hz`
Frequency of first fork ` = n . "Frequency of 56 th fork" = 2 n`
`:. n + (56 - 1)4 = 2n`
`:. n + 220 = 2 n`
`n = 220 Hz`

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