Question

Two tuning forks `A and B` give ` 4 beats//s` when sounded together . The frequency of `A is 320 Hz`. When some wax is added to `B` and it is sounded with `A , 4 beats//s per second` are again heard . The frequency of `B` is
A. `312 Hz`
B. `316 Hz`
C. `324 Hz`
D. `328 Hz`

Answer 1

Correct Answer - C
Since there is no change in beats . Therefore the original frequency of `B` is
` n_(2) = n_(1) + x = 320 + 4 = 324`