when the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is mieaured to be 35.7

Here, `r = 824.7xx10^6km.`
`theta = 35.72' = (35.72)/(60xx60)xx(pi)/(180)radian`
Diameter, I = ?
As `I = r theta :. I = 824.7xx10^6xx(35.72xxpi)/(60xx60xx180)km = 1.492xx10^5km`

when the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is mieaured to be 35.72' of arc. Calculate t

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