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It is a well known fact that during a total solar eclipes the disc of the moon almost completely covers the disc of the sun. From this fact and from the information you can gather from Solved Examples 3 and 4 on page 1//44, determine the approximate diameter of the moon.

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Solved Examples 2 and 3 on page `1//50` give us the following data :
Distance of moon from earht, `ME = 3.84xx10^8m`
Distance fo sun from earht, `ME = 1.496xx10^(11)m`.
Diameter of sun `AB = 1.39xx10^9m`
The situation during total solar eclipes is shwon in fig.
As `Delta^s` ABE of CDE are similar, therefore,
`CD = ABxx(ME)/(SE) = (1.39xx10^9xx3.84xx10^8)/(1.496xx10^(11)) = 3.5679xx10^6m`
` = 3567.9km`
This is the diameter of the moon.
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