Question

The velocity `upsilon` of a particle is given by `upsilon = A t^2 +Bt.` What are the dimensions of A and B ?

Answer 1

`A = (upsilon)/(t^2) = (LT^(-1))/(T^2) = LT^(-3) = [M^0 L^1 T^(-3)]`
`B = (upsilon)/(t) = (LT^(-1))/(T) = LT^(-2) = [M^0 L^1 T^(-2)]`