Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
78 views
in Physics by (79.4k points)
closed by
For a particle executing SHM, the displacement `x` is given by `x = A cos omegat`. Identify the graph which represents the variation of potential energy `(PE)` as a function of time `t` and displacement `x`.
image
(a) `I, III`
(b) `II, IV` (c ) `II, III`
(d) `I, IV`
A. I,III
B. II,IV
C. II,III
D. I,IV

1 Answer

0 votes
by (86.6k points)
selected by
 
Best answer
Correct Answer - A
We know that in `SHM`, at extreme position, `PE` is maximum when `t = 0, x = A`, i.e., at time `t = 0`, the particle executing `SHM` is at its extreme position. Therefore `PE` is maximum. Graphs `I` and `III` represent the above characteristics.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...