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A drop of olive oil of radius 0.3 mm spreads into a rectangular film of `30 cmxx15cm` on the water surface. Calculate the size of the oil molecule.

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Correct Answer - `2.51xx10^(-9)m`
`d = ("Volume of drop")/("Area of film") = ((4)/(3)pir^3)/(ixxb)`
`=(4)/(3)xx(22)/(7) (0.3xx10^(-3))^3/(30xx15xx10^(-4)) = 2.51xx10^(-9)m`

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