Question

In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is
A. 0.04
B. 0.14
C. 0.1
D. 0.07

Answer 1

Correct Answer - (b)
Here, `P = (a^3 b^2)/(cd)`
`(DeltaP)/(P) = +-(3(Delta a)/(a) + 2 (Delta b)/(b) + (Delta c)/(c ) + (Delta d)/(d))`
`(Delta P)/(P)xx100 = +- (3xx 1% + 2xx 2% +3% + 4%)`
`= +- 14%`