Question

If C represents capacitance and R represents resistance, then the unit of `CR^2` are
A. Henry
B. `("volt-second")/("ampare")`
C. `"volt"//"ampere"`
D. `"joule"//"ampere"^2`

Answer 1

Correct Answer - (a,b,d)
We know that `(L)/(R ) = t and RC = t`
`:. (L)/(R ) = RC or CR^2 = L`
Units of `CR^2` are the same us units of L, which is henry.
From `e= L (dl)/(dt), L = (e dt)/(dl) = ("volt sec")/("ampare")`
From `U = (1)/(2) LI^2, L = (2U)/(I^2) = ("joule")/("ampare"^2)`