Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
78 views
in Physics by (91.2k points)
closed by
An object of mass `m` is tied to a string of length `l` and a variable force F is applied on it which brings the string gradually at angle thit `theta` with the vertical. Find the work done by the force `F`
image.

1 Answer

0 votes
by (91.8k points)
selected by
 
Best answer
The various forces involved in the problem are shown in figure.
As the object is in equilibrium at every stage, therefore,
`mg=Tcostheta and F=Tsin theta`
`(F)/(mg)=(Tsintheta)/(Tcostheta)=tantheta`
`F=mg tan theta` ….(i)
Work done by the force,
`W=int_(0)^(theta)vecF.dvecs=int_(0)^(theta)F ds cos theta`
`=int_(0)^(theta)mg tantheta xx(ld theta). costheta`
`=mgl int_(0)^(theta)sind theta=mgl[-costheta]_(0)^(theta)`
`=-mgl(cos theta-cos 0^(@))`
`W=mgl(1-costheta)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...