Correct Answer - C
Here, `m=1kg`
`vec(F)=(2t hat(i)+3t^(2)hat(j))N,P=?`
From `F=ma=m(dupsilon)/(dt)`
`(dupsilon)/(dt)=(F)/(m)=(2that(i) +3t^(2)hat(j))/(1)`
`=(2t hat(i)+3t^(2)hat(j))m//s^(2)`
`dupsilon=(2that(i)+3t^(2)hat(j))dt`
`upsilon=int (2that(i)+3t^(2)hat(j))dt`
`=(2t^(2))/(2)hat(i)+(3t^(3))/(3)hat(j)=(t^(2)hat(i)+t^(3)hat(j))`
Now, `P=vec(F). vec(upsilon)=(2that(i)+3t^(2)hat(j)).(t^(2)hat(i)+t^(3)hat(j))`
`P=(2t^(3)+3t^(5))"watt"`