Correct Answer - B
Here `m_(1)=5 g =0.005 kg, u_(1)=600 m//s`,
`m_(2)=5 kg, u_(2)=0`
After collision, they will move with the same velocity `upsilon`.
As momentum is conserved
`m_(1)u_(1)+ m_(2)u_(2)=(m_(1)+m_(2))upsilon`
`:. upsilon=(m_(1)u_(1)+m_(2)u_(2))/(m_(1)+m_(2))`
`upsilon=(0.005xx600xx0)/((5+0.005))=0.6m//s=60 cm//s`