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in Physics by (79.4k points)
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A particle is projected at point A from an inclination plane with inclination angle `theta` as shown in figure. The magnitude of projection velocity is `vecu` and its direction is perpendicular to the plane. After some time it passes from point B which is in the same horizontal level of A, with velocity `vecv`. Then the angle between `vecu and vecv` will be
image
A. `theta`
B. `2 theta`
C. `pi-2 theta`
D. `90+ theta`

1 Answer

+1 vote
by (86.6k points)
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Best answer
Correct Answer - c
`alpha` is the required angle.
image
So `alpha=180^(@)-2 theta`

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