Question

Two bodies of masses `m` and `4m` are moving with equal linear momenta. The ratio of their kinetic energies is `:`

Answer 1

Here, `m_(1)=m`
`m_(2)=4m`
If `upsilon_(1), upsilon_(2)` are their respective velocities, then as
`p_(1)=p_(2)`
`m_(1)upsilon_(1)=m_(2)upsilon_(2)`
`(upsilon_(1))/( upsilon_(2))=(m_(2))/( m_(1))=4,`
`(E_(1))/(E_(2))=((1)/(2)m_(1)upsilon_(1)^(2))/( (1)/(2)m_(2)upsilon_(2)^(2))=(1)/(4)((4)/(1))^(2)=4`