Question

A car is moving along a stight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is mu, the shortest distance in which the car can be stopped is.
A. `(v_0^2)/(mug)`
B. `(v_0^2)/(4mug)`
C. `(v_0^2)/(2mug)`
D. `(2v_0^2)/(mug)`

Answer 1

Correct Answer - C
`(1)/(2)mv_0^2=fs=mugs`
`s=(v_0^2)/(2mug)`