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A block of mass `m`m remains stationary on a fixed inclined plane of inclination `theta` . If `mu`= coefficient of static friction the reaction of ground on the block is:
A. `mug costheta`
B. `mgcostheta`
C. `mgsintheta`
D. `mg darr`

1 Answer

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Best answer
Correct Answer - D
As block is stationary on inclined plane.
Hence friction force `=mgsintheta`
and normal reaction applied on the block `=mgcostheta`
Hence net reation on the block applied by inclied plane
`sqrt((mgsintheta)^(2)+(mgcostheta)^(2))=mg` upward

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