Correct Answer - A
The situation is shown in figure. For the mass `m` to be stationary, the tension in the string should provide the necessary centripetal force on the rotating mass `M` . Now
`T=mg` and `T=Mlomega^(2)` or `mg=mlomega^(2)`
or `m=(Mlomega^(2))/(g)` .
![image](https://learnqa.s3.ap-south-1.amazonaws.com/images/161076889317079123051610768893.png)