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A monkey of mass `20kg` is holding a vertical rope. The rope will not break when a mass of `25kg` is suspended from it but will break it the mass exeeds `25kg` . What is the maximum acceleration with which the monkey can climb up along the rope? `(g=10m//s^(2))` .
A. `10m//s^(2)`
B. `25m//s^(2)`
C. `2.5m//s^(2)`
D. `5m//s^(2)`

1 Answer

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Best answer
Correct Answer - C
Tension the string `=m(g+a)` =Breacking force
implies `20(g+a)=25xxg` implies `a=g//4=2.5m//s^(2)`

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