Question

A block of mass `m` is placed on a smooth inclined wedge ABC of inclination theta as shown in the figure. The wedge is given an acceleration `a` towards the right. The relation between a and theta for the block to remain stationary on the wedge is.

A. `a=g tantheta`
B. `a=(g)/(cosectheta)`
C. `a=costheta`
D. `a=(g)/(sintheta)`

Answer 1

Correct Answer - A
If the block is stationary, `macostheta=mgsintheta`
which gives `a=gtantheta` .