Net pulling force `=2 mg -mg =mg`
Total mass `= m+ m+ m =3m`
Acceleration `a = (mg)/(3m) = (g)/(3)`
Considering block `A`,
`T_(1) -mg = ma, T_(1) =mg +ma`
`T_(1) = mg +a ((g)/(3)) rArr T_(1) = (4)/(3) mg`
`mg - T_(2) =ma rArr T_(2) =mg -ma`
`rArr T_(2) =mg -(mg)/(3) =(2)/(3) mg`
Acceleration `a=(mg)/(3m)=g/3`

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