Question

A particle of mass 10 g moves along a circle of radius `6.4` cm with a constant tangential acceleration. What is the magnitude of this acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to `8xx10^(-4)`J by the end of the second revolution after the beginning of the motion?
A. `0.15" ms"^(-2)`
B. `0.18" ms"^(-2)`
C. `0.2" ms"^(-2)`
D. `0.1" ms"^(-2)`

Answer 1

Correct Answer - D
(d) `W_("Tengential")=DeltaKE=K_(f)-K_(i)=K_(f)-0`
`(ma_(T))xx5=8xx10^(-4)`
`a_(T)=(8xx10^(-4))/(10^(-2)(2pirxx2))=(2xx10^(-2))/(pixx2pixx10^(-2))=0.1 ms^(-2)`