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A block A of mass 3kg and another block `B` of mass `2kg` are connected by a light inextensible string as shown in figure. If the coefficient of friction between the surface of the table and A is 0.5 What maximum mass `C` is to be placed on A so that the system is to be in equlibrium
image .
A. `3kg`
B. `2kg`
C. `1kg`
D. `4kg`

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Best answer
Correct Answer - C
For equilibrium `f = mum_(B) g ,f = mu (m_(A) +m_(C))g` .

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