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A man weighs `80kg` . He stands on a weighing scale in a lift which is moving upwords with a uniform acceleration of `5m//s^(2)` . What would be the r

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A man weighs `80kg` . He stands on a weighing scale in a lift which is moving upwords with a uniform acceleration of `5m//s^(2)` . What would be the reading on the scale?
A. 400 N
B. 800 N
C. 1200 N
D. zero
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Correct Answer - C
Weight is indicated by normal reaction.
image
`N_(0)-Mg=Ma`
`N_(0)=W=M(g+a)`
=80(10+5)
=1200N
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