Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
190 views
in Physics by (91.8k points)
closed by
A disc of radius `0.5 m` is rotating about an axis passing through its centre and perpendicular to its plane. A tangential force of `2000 N` is applied to bring the dics to rest `2 s`. Calculate its abgular momentum.

1 Answer

0 votes
by (91.2k points)
selected by
 
Best answer
Here, `r = 0.5m, F = 2000N, t = 2 s`
Final angular momentum, `L_(2) = 0`,
Initial angular momentum, `L_(1) = ?`
torque applied, `tau = - F xx r = - 2000 xx 0.5`
`= - 1000 N-m`
As `tau= (L_(2) - L_(1))/(t)`
`:. - 1000 = (0 - L_(1))/(2), L_(1) = 2000 kg m^(2) s^(-1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...