Question

A constant torque is acting on a wheel. If starting from rest, the wheel makes n rotations in t seconds, show that the angular
acceleration is given by `alpha = (4pi n)/(t^(2)) rad s^(-2)`.

Answer 1

Here, `omega_(1) = 0`. Number of rotations in `t sec = n`
`:.` angular displacement, `theta = 2pi n`
As `theta = omega_(1) r + (1)/(2) alpha t`
`:. 2pi n = 0 + (1)/(2) alpha t^(2), alpha = (4pi n)/(t^(2)) rad//s^(2)`