Question

One litre of helium gas at a pressure `76 cm`. Of Hg and temperature `27^(@)C` is heated till its pressure and volume are double. The final temperature attained by the gas is:
A. `327^(@)C`
B. `927^(@)C`
C. `1027^(@)C`
D. `827^(@)C`

Answer 1

Correct Answer - B
Initial volume of the gas `V_(1) = 1` litre initial pressure the gas `P_(1) = 70 "cm of Hg"`
Final pressure of the gas `P_(2) = 2 xx 76 = 152 "cm of Hg"`
Final volume of gas `V_(2) = 2 "litre"`
According the Gay Lussac law we have
`(P_(1)V_(1))/(T) = (p_(2)V_(2))/(T_2) or (76XX)/(300) = (152XX2)/(t_2)`
`(1)/(300) = 4/(t_2) OR t_(2)B = 4 XX 300 = 1200k = 927^(@)c`.